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288=2x^2
We move all terms to the left:
288-(2x^2)=0
a = -2; b = 0; c = +288;
Δ = b2-4ac
Δ = 02-4·(-2)·288
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-2}=\frac{-48}{-4} =+12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-2}=\frac{48}{-4} =-12 $
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